PDA

View Full Version : Tough Sequence problem


darkmass
Aug1-04, 02:14 AM
Find a formula for the givin sequence:

0, 1 , 1 , 2 , 2 , 3 ,3 ,4 ,4 ............


thanks. any help would be appreciated.

cookiemonster
Aug1-04, 02:32 AM
a_{2n} = a_{2n-2} + 1
a_{2n+1} = a_{2n-1} + 1
a_0 = 0
a_1 = 1

cookiemonster

Muzza
Aug1-04, 02:51 AM
Or a_n = floor( (n + 1)/2 ), n >= 0.