View Full Version : Weird limit…
does...
\lim_{n \rightarrow \infty} \frac{n}{(n!)^\frac{1}{n}} = e
If not, is it divergent?
mathwonk
Aug2-04, 05:37 PM
isnt there somethiong called stirlings formula for n! ?? Maybe you could use that and lhopital.
mathwonk
Aug2-04, 05:40 PM
well i just looked up stirling and it seems to suggest at a quick calculation, not guaranteed, that this limit is e/sqrt(2pi)
e/(2pi)^(1/2) aprox= 1.0844
my calc can do the limit up to 200 and it equals about 2.67021... that's why i thought it may = e
With Stirlings approximation: N!\approx N^Ne^{-N}, you indeed get:
\frac{N}{(N^Ne^{-N})^{\frac{1}{N}}}=\frac{N}{Ne^{-1}}=e
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