simple inertia

[a.mlw.walker]

So I have a piston connected to a flywheel. If i push the piston with a force F, how does the equation of motion look? I'm not confident about putting inertias into the same equation as accelerations?

F = ma

F = I(theta'')

The force is changing with time.

EDIT:

So i have just realised that T = Ia, a is angular acceleration.

So if i find resultant force of piston acting along line of tangential velocity on the flywheel, then moultiply it by r of the flywheel,

Fr = Ia, then rearrange for a and i have angular acceleration of flywheel?

[tiny-tim]

Hi a.mlw.walker! :smile:

(have a tau: τ and a theta: θ and an omega: ω and an alpha: α :wink:)
So i have just realised that T = Ia, a is angular acceleration.

So if i find resultant force of piston acting along line of tangential velocity on the flywheel, then moultiply it by r of the flywheel,

Fr = Ia, then rearrange for a and i have angular acceleration of flywheel?

That's right …

the standard linear equations apply, with τ I θ ω and α instead of F m s v and a. :wink: