difference in oh-

[clavin]

is there any difference in oh- from a strong base than from a weak base apart from concentration?
second
lets say we have this reaction
ch3cooh + oh- => ch3coo- + h2o
in this reaction my book says the reaction will go to completion
but isnt acetic acid a weak acid. so shouldnt the disassociation should be partial
therefore why does the reaction go to completion?
also one more example
ch3cooNa=> ch3coo- + Na+
here again the disassociation is full
as Na+ comes from a strong acid
so why the dissociation extent of Na affect that of ch3coo-

[Borek]

All OH- are identcial, and indistinguishable.

No such thing as ch3cooh - please write formulas correctly.

Neutralized acetic acid slightly hydrolizes, so stating that the reaction goes to completion is an aproximation - but a good one.

Na+ doesn't come from an acid. I have no idea what you are asking about.

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