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biguelo
May1-10, 04:17 PM
Hi,

I have a 480 V, 200 kVAr and 60 Hz capacitor bank. I need to move this bank to a location with 390 V and 50 Hz, I wonder what would be the resulting power of the bank.

Regards.

n.karthick
May20-10, 12:46 AM
Find value of capacitive reactance at 60 Hz
X_{60}=\frac{P}{V^2}. Now its value at 50 Hz is found from
\frac{X_{50}}{X_{60}}=\frac{60}{50}.
From the value of X_{50} and using new voltage 390 V you can find resulting power rating of your capacitor bank.

biguelo
May20-10, 08:30 AM
Thanks for the reply.