Single Slit Diffraction Problem?

[abrowaqas]

1. The problem statement, all variables and given/known data

Monochromatic light of wavelength 441 nm falls on a narrow slit. on a screen 2.16m away, the distance between the second minimum and the central maximum is 1.62 cm. a) calculate the angle of diffraction thetta of the second minimum. b) find the width of the slit? Rensick Halliday 5th edition. page no. 977

2. Relevant equations

dsin(theeta) = m lamda(wavelendth)

3. The attempt at a solution

[Tusike]

In your formula, since we're talking about the second minimum, m = 2*(2*pi) (since interference happens every deltaS = 2pi*lambda) .
And sin(theta) =~ 1.62cm / 2.16m. From that you should get the results.

[abrowaqas]

Thanks . yes i tried it... its solved