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xowe
Sep6-04, 03:27 PM
Erm, I have another problem. This question confused me, I'm not sure how to do it. Help would be apprecaited. Thanks
The midpoint of line QS is the origin. Point Q is located in Quadrant II. What quadrant contains point S?
Same with this one.
M(5,12) is the midpoint of line AB. The coordinates of point A are (2,6). What are the coordinates of point B?

Muzza
Sep6-04, 03:30 PM
Draw a picture. Take a point Q in the second quadrant, and draw a line from Q to the origin. Into which quadrant can you extend the line (so that it is still straight)? Now, which quadrant must S lie in?

xowe
Sep6-04, 04:18 PM
Quadrent 4 I think. Ok, I think I get it. Thanks

HallsofIvy
Sep7-04, 06:53 AM
In general, the midpoint of the line segment from (x0,y0) to (x1,y1) is the "average" of the two: ((x0+x1)/2, (y0+y1)/2).

In this case you are told that the midpoint of the line segment from A:(2,6) to the point B (call its coordinates (x,y)) is (0,0). That is (2+ x)/2= 0 and (6+y)/2= 0. It should be easy to see that B is (-2, -6).