Finding the limit of lim_(h-->0) (f(1+h,2) - f(1,2))/h

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Homework Help Overview

The discussion revolves around finding the limit of a difference quotient involving a function of two variables, specifically as \( h \) approaches 0. The context includes a function defined as \( z = 2x^3 + xy^2 - 6y \) and the limit expression provided by the original poster.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to substitute specific values into the function and explore the implications of doing so. There is a suggestion to expand polynomials and look for cancellations. Questions arise regarding the necessity of finding partial derivatives and clarifications about the correct values for \( x \) and \( y \) in the limit expression.

Discussion Status

The discussion is active, with participants offering hints and questioning assumptions about the function's variables. There is a mix of approaches being considered, including polynomial expansion and derivative concepts, but no consensus has been reached on a specific method to proceed.

Contextual Notes

Participants are navigating the implications of substituting values into the function and the definitions of the variables involved in the limit expression. The original poster expresses uncertainty about whether the function is necessary for calculating the limit.

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I have a function [tex]z=2x^3+xy^2-6y[/tex]
I need to find the limit of the following:
[tex]\lim_{\substack{h\rightarrow 0}} \frac{f(1+h,2)-f(1,2)}{h}[/tex]
I don't know if the function is required to calculate this limit, so I just wrote it as well. I just need some hint on where to begin, and how to approach this type of limit...
 
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Replace x and y with the specified values, expand your polynomials, subtract, look for cancellation and divide the result by h - then take your limit! :-)
 
Won't I need to find the partial derivatives?
 
That's exactly what you're doing.
 
Hmm...I should replace x and y with the specified values, those are 1 and 2 ?
If I do that in the function then I get the value -6. Where does that leave me?
 
No, (x, y) = (1, 2) for f(1, h) but (x, y) = (1+h, 2) for f(1+h, 2).
 

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