PDA

View Full Version : evaluating complex numbers


Allday
Sep12-04, 07:03 PM
How do you evaluate this expression algebraically.


e^{\sqrt{i}}

robphy
Sep12-04, 07:23 PM
Since i=exp(i*pi/2), you can determine easily sqrt(i) in polar form, then in rectangular form: a+bi. Then you can evaluate exp(a+bi).

Tide
Sep12-04, 07:26 PM
If you take i = e^{i \frac {pi}{2}} then \sqrt i = e^{i \frac {pi}{4}}. Just write it in trig form and put into your expression.

Allday
Sep12-04, 08:12 PM
easy peasy. thanks

existence
Sep12-04, 10:40 PM
Not quite. Don't forget the second root exp[i(pi/4 + pi)].

Allday
Sep13-04, 12:05 AM
Ahh yes, those pesky multiple values. That complex plane will eventually bend to my will.