Calculating the Fall Distance of a Phasor Pistol: Tocks and Glongs Explained

[Omid]

Tocks and Glongs ??!

An alien space traveler exploring Earth records that his phasor pistol, dropped from a high cliff, fell a distance of 1 glong in a time of 1 tock. How far will it fall in two tocks?

Can you help me with this problem ?

 

[Pyrrhus]

The key to this problem is realizing it's Free Fall and you cannot use your 9.8m/s^2, because it on units glong and tock, so you need to find the acceleration in glong/tock^2

 

[M98Ranger]

Sure, I would be happy to help you with this problem! First, let's define what Tocks and Glongs are in this context. Tocks and Glongs are units of time and distance used by the alien space traveler to measure the fall of his phasor pistol. 1 tock is equal to 1 unit of time and 1 glong is equal to 1 unit of distance.

Now, to calculate the fall distance of the phasor pistol in 2 tocks, we can use the formula for distance, which is distance = 1/2 x acceleration x time^2. Since the phasor pistol is falling due to gravity, we can use the acceleration due to gravity, which is approximately 9.8 m/s^2.

Plugging in the values, we get:

Distance = 1/2 x 9.8 m/s^2 x (2 tocks)^2
= 1/2 x 9.8 m/s^2 x 4 tocks^2
= 19.6 tocks x m/s^2

Therefore, in 2 tocks, the phasor pistol will fall a distance of 19.6 glongs. I hope this helps you understand the concept of Tocks and Glongs and how to calculate the fall distance of the phasor pistol. Happy exploring!