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nomi
Sep14-04, 07:57 PM
http://img.photobucket.com/albums/v124/mugenlude99/myhw1.jpg

did i do this correct?

thanks

Pyrrhus
Sep14-04, 08:08 PM
There's something wrong, you shouldn't do u = e^-x dx, only u = e^-x and when you say -du = e^-x dx, you have to substitute it completely in the integral i mean -\int { tan(u)du}

nomi
Sep14-04, 08:15 PM
There's something wrong, you shouldn't do u = e^-x dx, only u = e^-x and when you say -du = e^-x dx, you have to substitute it completely in the integral i mean -\int { tan(u)du}
i think i know what you're saying, but i took the -1 out since its a constant.

:confused:

Pyrrhus
Sep14-04, 08:31 PM
that's ok, i'm talking about your substitution... You should not pick u = e^-x dx, why without dx? you will know why not later, and if you have a -du = e^-x dx, you should not have -\int {tanu dx} you should have -\int {tanu du} see what i mean?, remember in your du you have the dx.

nomi
Sep14-04, 09:05 PM
that's ok, i'm talking about your substitution... You should not pick u = e^-x dx, why without dx? you will know why not later, and if you have a -du = e^-x dx, you should not have -\int {tanu dx} you should have -\int {tanu du} see what i mean?, remember in your du you have the dx.
oh sorry yeah that is a careless mistake, but other than the dx it's ok?

NateTG
Sep15-04, 11:25 AM
oh sorry yeah that is a careless mistake, but other than the dx it's ok?

Aside from that it looks good to me.

nomi
Sep15-04, 12:15 PM
Aside from that it looks good to me.
ok thanks a lot guys :)