Whatupdoc
Sep15-04, 01:54 AM
A .22 rifle bullet, traveling at 350 m/s, strikes a block of soft wood, which it penetrates to a depth of 0.130 m. The block of wood is clamped in place and doesn't move. The mass of the bullet is 1.80 g. Assume a constant retarding force.
1.) What force, in newtons, does the wood exert on the bullet?
using Newton's Second Law (F=ma)
first i had to find a
v^2f = V(0)^2 + 2ax <--- equation of motion
0=350^2+2(a)(0.130)
a = 471153.8462
then plug in known values for newton's second law
F = (1.80)(471153.8462) = 848076 N
or 8.48×10^5 N
but it's the wrong answer, can someone help?
1.) What force, in newtons, does the wood exert on the bullet?
using Newton's Second Law (F=ma)
first i had to find a
v^2f = V(0)^2 + 2ax <--- equation of motion
0=350^2+2(a)(0.130)
a = 471153.8462
then plug in known values for newton's second law
F = (1.80)(471153.8462) = 848076 N
or 8.48×10^5 N
but it's the wrong answer, can someone help?