Freefall Acceleration of a Raindrop

[VinnyCee]

I have an answer that does not seem right:

The raindrop falls from 1700m high with constant acceleration of 9.81 m / s^2
What is the velocity of the raindrop not considering any resistance?

i used y - yo = vo * t - (1/2) g t^2 to get the time to hit the ground at 18.62 seconds.

I then plugged that into v = vo + a t to get 182.63 m / s which seems kind of fast for a raindrop, right? Can anyone help? Please?

[Integral]

So that would imply, that in reality, you cannot ignore air resistance, if you want a meaningful value for the velocity of a rain drop. I did not check your numbers but they do not seem unreasonable, for this ideal but unrealistic scenario.

Edit, checked your numbers they are right in all of the signifiant digits.

[VinnyCee]

Thank you for the help :approve: I always get worried that I did something wrong when numbers do not turn out to appear reasonable.

[arildno]

Check out Stokes' resistance law on a sphere moving through a viscous fluid.
This yields a fall velocity consistent with experiments on the fall velocity of fog droplets.