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Hello everyone! Can anyone tell me a formula (or a way to derive) this integral?
\int|f(x)|dx
where f(x) is a real, continuous function of x in the vector space C^\infty. So far, all I've figured out is that odd-order integrations are related to the signum function.
Thanks!
PrudensOptimus
Sep17-04, 09:34 PM
Derive or find the area under |f(x)|?
|f(x)| = f(x), if x >=0; -f(x), if x<0
so ∬ |f(x)| dx has 2 solutions: F(x), and -F(X), where F(X) is the antiderivative of f(x).
Derive or find the area under |f(x)|?
|f(x)| = f(x), if x >=0; -f(x), if x<0
so ∬ |f(x)| dx has 2 solutions: F(x), and -F(X), where F(X) is the antiderivative of f(x).
No, |f(x)| = f(x) if f(x) >= 0 and -f(x) if f(x) < 0.
I recommend breaking up the integral into separate domains as I've indicated and integrating piecewise.
PrudensOptimus
Sep18-04, 12:28 AM
No, |f(x)| = f(x) if f(x) >= 0 and -f(x) if f(x) < 0.
I recommend breaking up the integral into separate domains as I've indicated and integrating piecewise.
Stop repeating my answers :p
Stop repeating my answers :p
LoL! Man, I've just GOTTA get some reading glasses! :bugeye:
Lonewolf
Sep18-04, 04:55 AM
He wasn't repeating your answers. Prudens used x, while Tide correctly used f(x).
PrudensOptimus
Sep18-04, 09:58 AM
what i really meant was f(x)... but i was thinking about beer.
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