View Full Version : Theorem name
hedlund
Sep19-04, 07:54 AM
What is the theorem that states if \Omega is a polynom with degree > 1 with real coefficients. If there exists a complex number z = a + bi such that \Omega(a+bi)=0 then \overline{z} = a - bi is also a root of \Omega ? For \Omega(x) = x^2 + px + q with p and q real then if a+bi is a root then a-bi is also a root if b \neq 0 , that one is easy but I don't think it's easy for degree > 2 to prove it that's why I'm search for it's name.
matt grime
Sep19-04, 08:15 AM
it doesn't have a name, as far as i know, and it is easy to prove. if z is a root of P, then z* is a root of P*, where * denotes conjugation, and by P*, I mean the polynomial where you replace the coeffs with their conjugates. (You understand that (uv)*=u*v*?)
TenaliRaman
Sep19-04, 08:56 AM
It does get mentioned along with FTA but i wouldn't bet on it having some special name.
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