luma
Oct10-10, 12:11 PM
http://img219.imageshack.us/img219/6725/diagramt.png
So I was doing this usual physics type question thing which goes along the lines kind of like this:
2 balls are constrained to a frictionless ring and collide elastically. What is their after velocities? Easy question using,
\frac{1}{2}m_{1}u_{1}^{2}+\frac{1}{2}m_{2}u_{2}^{2 }=\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^ {2}
m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}
I got the (correct) answers of -1 and 4 for the after speeds.
The thing that confuses me, is that since the collision is elastic, if we repeat it for the next collision that happens on the ring then we will get the same answers of -1 and 4... What does this mean? It's saying that the balls will just pass through each other???
So I was doing this usual physics type question thing which goes along the lines kind of like this:
2 balls are constrained to a frictionless ring and collide elastically. What is their after velocities? Easy question using,
\frac{1}{2}m_{1}u_{1}^{2}+\frac{1}{2}m_{2}u_{2}^{2 }=\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^ {2}
m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}
I got the (correct) answers of -1 and 4 for the after speeds.
The thing that confuses me, is that since the collision is elastic, if we repeat it for the next collision that happens on the ring then we will get the same answers of -1 and 4... What does this mean? It's saying that the balls will just pass through each other???