What's the Probability of Finding a Quantum Particle in Each Box?

  • Thread starter Thread starter Axiom17
  • Start date Start date
  • Tags Tags
    Particle Quantum
Click For Summary
SUMMARY

The probability of finding a quantum particle in two identical boxes, A and B, is determined using the wavefunction \(\psi(r)\). For box A, \(\psi(r) = 1+i\) and for box B, \(\psi(r) = 1-i\). The probability densities are calculated as \(P1 = 5\) for box A, \(P2 = 2\) for box B, and \(P3 = 2\) for elsewhere. Normalizing these values results in the probability of finding the particle in box B being \(p2 = \frac{2}{9}\).

PREREQUISITES
  • Understanding of quantum mechanics and wavefunctions
  • Familiarity with probability density calculations
  • Knowledge of normalization in quantum mechanics
  • Basic proficiency in complex numbers
NEXT STEPS
  • Study quantum mechanics wavefunction normalization techniques
  • Learn about probability density functions in quantum systems
  • Explore complex number operations in quantum mechanics
  • Investigate the implications of identical particles in quantum theory
USEFUL FOR

Students and educators in quantum mechanics, physicists analyzing wavefunctions, and anyone interested in the probabilistic nature of quantum particles.

Axiom17
Messages
70
Reaction score
0

Homework Statement



A quantum particle is described by the wavefunction [itex]\psi(r)[/itex]. There are 2 identical boxes (A & B).. what's the probability of finding the particle in each box?

Homework Equations



[tex]\psi(r)= \left\{ {\begin{array}{ll}<br /> <br /> 1+i & if A\\<br /> 1-i & if B\\<br /> 0 & if elsewhere\\<br /> <br /> \end{array}} \right[/tex]

The Attempt at a Solution



I'm really not sure where to start with this :frown: I see that I have the wavefunction [itex]\psi[/itex] for each box (and elsewhere), but I'm not sure what to do as far as the calculations.. hopefully just need a bit of a hint to get me going with it.
 
Last edited:
Physics news on Phys.org
Sorry, but I don't know how to use Latex, so please try to follow what I think:

|psi|² is the probability density, let's call it P1 for the first box, P2 for the second en P3 for the third.

P1=(1-2i)(1+2i)=5
P2=(1-i)(1+i)=2
P3=(1+i)(1-i)=P2=2

Because the probability is normalized, we have to divide by P1+P2+P3=9 to get p1, p2 and p3. This gives that the probability p2 to find it in the second box is 2/9.
 
Ok thanks for that I get it now :approve:
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
16
Views
3K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
16
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
Replies
1
Views
3K
Replies
14
Views
3K