Solve Motion Problem: 50 m Drop Time & Velocity

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Homework Help Overview

The problem involves a hot air balloon descending and a passenger dropping a camera from a height of 50 meters. The subject area pertains to kinematics, specifically motion under gravity and the effects of initial velocity on the time of descent and final velocity.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply a kinematic equation to determine the time it takes for the camera to reach the ground and questions their result. Some participants suggest that the issue may relate to sign conventions in the problem setup.

Discussion Status

The discussion is ongoing, with participants exploring the implications of sign conventions on the calculations. There is mention of adjusting the final position to reflect the downward direction, and some guidance is offered regarding the accuracy of gravitational acceleration values.

Contextual Notes

Participants are grappling with the correct application of sign conventions and the choice of gravitational acceleration, with a specific focus on how these factors influence the calculations for time and velocity.

mikep
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can someone help me with this problem? A hot air balloon is descending at a rate of 2.0 m/s when a passenger drops a camera. (a) If the camera is 50 m above the ground when it is dropped, how long does it take to reach the ground? (b) What is its velocity just before it lands? Let upward be the positive direction for this problem.

i did part a by this formula. 50 = (-2.0m/s)t + (1/2)(-10m/s2)t2
s2 = s squared t2 = t squared
i tried to solve for t and i got 2.9, but that not the right answer. anyone know what i did wrong?
 
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sign convention problem

It's a sign convention problem. Compared to where it starts to fall, the final position is -50 m, not +50 m.
 
ok so if i change the sign to -50 i get t = 2.96 that's what i had before. its not right
 
Last edited:
mikep said:
ok so if i change the sign to -50 i get t = 2.96 that's what i had before. its not right
What makes you think that your answer is incorrect? (Note that you'll get a slighty more accurate answer using g = 9.8 m/s^2.)
 

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