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mwhowell
Nov8-10, 11:53 AM
1. The problem statement, all variables and given/known data

Consider the following equation in y: Ay2 – 3y + 4 = 0.

What is the range of possible values for A such that the two roots are both real?



2. Relevant equations



3. The attempt at a solution

Not sure how to approach this problem.

fzero
Nov8-10, 01:04 PM
Can you express the roots in terms of A? Do you know what the discriminant is for a quadratic equation?

mwhowell
Nov8-10, 01:43 PM
what is a discriminant?

Mark44
Nov8-10, 01:48 PM
The discriminant is the quantity inside the square root in the quadratic formula. You know the quadratic formula, right?

mwhowell
Nov8-10, 01:51 PM
yea i know the quadratic formula but we are not given the value inside the square root. all the info we are given is stated in the problem up there

Mark44
Nov8-10, 02:02 PM
The value of the discriminant tells you how many real solutions there are.

If the discriminant > 0, there are two real solutions.
If the discriminant = 0, there is one real solution.
If the discriminant < 0, there are no real solutions (there are two complex solutions).

Do you know how to use the quadratic formula?

mwhowell
Nov8-10, 02:09 PM
yea i know how to use the quadratic forumla but i am still really confused

fzero
Nov8-10, 02:20 PM
Well as a first step, can you use the quadratic formula to determine an expression for the roots of A y2 – 3y + 4 = 0? Once you do that, you might want to carefully examine the quantity in the square root.

symbolipoint
Nov8-10, 03:51 PM
Basically they are trying to say that the discriminant must be greater than or equal to zero; find A.

eumyang
Nov8-10, 03:54 PM
Basically they are trying to say that the discriminant must be greater than or equal to zero; find A.
Not greater than or equal to zero; just greater than. The original problem:
Consider the following equation in y: Ay2 – 3y + 4 = 0.

What is the range of possible values for A such that the two roots are both real?

symbolipoint
Nov8-10, 04:16 PM
Yes. I see. TWO ROOTS REAL. Otherwise only one root.