Integrating gravity(g)= -9.8m/s

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Discussion Overview

The discussion revolves around the integration of gravity, specifically the constant acceleration due to gravity at -9.8 m/s², and its application in deriving motion equations. Participants explore the mathematical steps involved in this integration, including limits and the formulation of equations related to velocity and displacement.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that integrating gravity leads to motion equations with constant acceleration and provides several mathematical expressions related to velocity and displacement.
  • Another participant questions the clarity of the integration process and the limits of the integral.
  • A different participant expresses uncertainty about the correctness of their earlier claims and seeks assistance in deriving torque.
  • There is a mention of confusion regarding the distinction between Newton the physicist and Newton the mathematician, with references to force and acceleration definitions.
  • One participant expresses a desire to understand how gravity was experimentally determined.
  • Another participant points out a potential mistake in one of the mathematical lines presented by the first participant.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the correctness of the mathematical claims, as there are indications of confusion and potential errors in the presented equations. Multiple competing views and uncertainties remain evident throughout the discussion.

Contextual Notes

There are unresolved mathematical steps, particularly regarding the integration limits and the derivation of torque. Some assumptions about the integration process and the application of physics concepts may not be fully articulated.

Alem2000
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correct me if I am wrong...

By integrating gravity(g)= -9.8m/s...you get the motion equations with constant acceleration

I didnt know how to set the limits of the integral...LATEX IS TUFF
[tex]d\vec{a}=(-g)dt[/tex] 1

[tex]\int_{\vec{V}_0}^{\vec{V}}dv=\int_{t_0}^{t_1}{-g}dt[/tex] 2

[tex]\Delta{\vec{v}}=(-g)t[/tex] 3

[tex]\vec{v}dt=d\vec{r}[/tex] 4

[tex]\d\vec{r}=(\vec{v}_0+(-g)t)dt[/tex] 5

[tex]\intd\vec{r}=\int(\vec{v}_0+(-g)tdt[/tex] 6

[tex]\Delta\vec{r}=\vec{v}_0t+1/2(-g)t^2[/tex] 7

[tex]\Delta{\vec{v}}=\int{\vec{v}_0}dt[/tex] 8


HOLD ON A SEC IM TRYN TO LATEX...Can anyone prove the force equations?

HI merons dad
 
Last edited:
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Are you talking about Newton the physicist or Newton the mathematician?

Physics: force = mass times acceleration or change in momentum per unit time

acceleration = time rate of change of velocity

Mathematics: [itex]a = \frac {dv}{dt}[/itex]
 
Gravity

Did I make some mistakes...?..i think i fixed them all. Can anyone show how to derive Torqu?

[tex]\Delta{\vec{v}}=(-g)t[/tex] 3

[tex]\vec{v}dt=d\vec{r}[/tex] 4

[tex]d\vec{r}=(\vec{v}_0+(-g)t)dt[/tex] 5

[tex]\intd\vec{r}=\int(\vec{v}_0+(-g)tdt[/tex] 6

[tex]\Delta\vec{r}=\vec{v}_0t+1/2(-g)t^2[/tex] 7

[tex]\Delta{\vec{v}}=\int{\vec{v}_0}dt[/tex] 8
 
Last edited:
Oooops I ment to put that on the physics posts not calculus :frown: :frown:
 
how did he figure it out..experiment?
 
Last edited:
No English!
 
Alem, there appears to be a problem with your line #8.
 

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