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buffgilville
Sep28-04, 02:24 AM
Compute the limit of:
1) f(x) = 2(square root of (x^2 - 1))/(x+1)

as x approaches -1 from the right.

2) f(x) = 3(x+2)/(absolute value of x + 2)

as x approaches -2 from the left.

I got does not exist for both because and x>-1 and x<-2, respectively. Am I right?

Leong
Sep28-04, 02:40 AM
\begin{multline*}
\begin{split}
&f(x)=\frac{3(x+2)}{|x+2|}\\
&Approches\ -2\ from\ the\ left:\\
&x+2<0;\ |x+2|=-(x+2)\\
&f(x)=\frac{3(x+2)}{-(x+2)}\\
&f(x) approaches -3.
\end{split}
\end{multline*}