Silly Gravity / Radius Question

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    Gravity Radius
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SUMMARY

A planet with the same mass as Earth but with gravitational acceleration of g/2 requires a radius that is approximately 1.414 times greater than Earth's radius. This conclusion is derived from the gravitational force equation, where gravitational acceleration (g) is inversely proportional to the square of the radius (r). By manipulating the equation F = G(m1*m2)/r^2, it is established that to halve the gravitational acceleration, the radius must be increased by the square root of 2.

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atrain77a
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I think this is pretty basic, but I'm obviously missing something. Here's the ?:

A planet has the same mass as earth, but it's gravitational acceleration is g/2. What is the radius of the planet?


What's the relationship here? -AT77A
 
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Well, let me see (correct me if I'm wrong)

[tex]\vec{F} = G \frac{m_{1}m_{2}}{r^2} \vec{r}[/tex]

[tex]m_{2} \vec{g} = G \frac{m_{1}m_{2}}{r^2} \vec{r}[/tex]

[tex]\vec{g} = G \frac{m_{1}}{r^2} \vec{r}[/tex]

so, if g/2

[tex]\frac{\vec{g}}{2} = \frac{G \frac{m_{1}}{r^2}}{2} \vec{r}[/tex]
 
For a constant mass, to cut g in half, you have to increase the radius by 1.414... (sqrt(2)).
 

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