Solve Boolean Identities: xy+x’z+yz’=xy+x’z

  • Thread starter Thread starter syedejaz
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around solving a Boolean algebra equation, specifically whether the expression xy+x’z+yz’ equals xy+x’z. Participants seek to apply basic Boolean identities to demonstrate this equality.

Discussion Character

  • Homework-related
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant requests help in solving the equation using basic Boolean identities.
  • Another participant asks for a list of basic Boolean identity equations and their applicability to the problem.
  • Several participants question the correctness of the original equation, noting that the left-hand side (LHS) and right-hand side (RHS) differ due to an extra term on the LHS.
  • One participant suggests checking the equation using Karnaugh maps to confirm the difference between the LHS and RHS.
  • A later reply indicates that the university corrected the original equation, providing a new version: xy+x’z+yz=xy+x’z.

Areas of Agreement / Disagreement

Participants express disagreement regarding the correctness of the original equation, with some asserting that the LHS does not equal the RHS. The discussion remains unresolved regarding the application of Boolean identities to the corrected equation.

Contextual Notes

The discussion highlights the importance of accurately copying equations and the potential for errors in problem statements, which can lead to confusion in applying mathematical manipulations.

syedejaz
Messages
5
Reaction score
0
Dear all please help me in solving this question:
I tried my best but I was not able to solve.

Using the basic identities of Boolean algebra show that :
xy+x’z+yz’=xy+x’z


Kindly help me.
 
Physics news on Phys.org
syedejaz said:
Dear all please help me in solving this question:
I tried my best but I was not able to solve.

Using the basic identities of Boolean algebra show that :
xy+x’z+yz’=xy+x’z


Kindly help me.

Welcome to the PF.

What are the basic Boolean identity equations? Please list them for us, and tell us which ones you think might apply.
 
berkeman said:
Welcome to the PF.

What are the basic Boolean identity equations? Please list them for us, and tell us which ones you think might apply.

Thank you so much
here is the table from my course book
Untitled-1-2.jpg
 
Last edited:
BTW, are you sure you copied the equation down correctly?

xy+x’z+yz’=xy+x’z


The lefthand side (LHS) and righthand side (RHS) are the same, except for one extra term on the LHS...
 
berkeman said:
BTW, are you sure you copied the equation down correctly?

xy+x’z+yz’=xy+x’z


The lefthand side (LHS) and righthand side (RHS) are the same, except for one extra term on the LHS...

And if you check this with two Karnaugh maps (one for LHS and one for RHS), they differ...
 
berkeman said:
BTW, are you sure you copied the equation down correctly?

xy+x’z+yz’=xy+x’z


The lefthand side (LHS) and righthand side (RHS) are the same, except for one extra term on the LHS...

yes offcourse
 
hello no body knows ): please help me I have to submit my Assigment tomorrow.
 
syedejaz said:
yes offcourse

What do you mean "of course"? The LHS does not equal the RHS, so how can you use any manipulations to show that they are equal?
 
berkeman said:
What do you mean "of course"? The LHS does not equal the RHS, so how can you use any manipulations to show that they are equal?

Dear I am very sorry.
Our university corrected the mistake . They published it on the web.
here is the correct

xy+x’z+yz=xy+x’z

Thanks
 

Similar threads

Replies
15
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
3
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K