GR Stuff

[latentcorpse]

In the notes attached here:
http://www.physicsforums.com/showthread.php?p=3042019#post3042019
(apparently I can't attach the same thing in multiple threads????)
I have quite a few problems with one of the proofs. In the proof of the proposition on p15,

a) he says to note that \nu(0)=0. why is this?

b) he goes from
\{ \frac{d}{dt} [ \alpha ( x^\mu ( \lambda(t)) - x^\mu(p)) + \beta (x^\mu(\kapa(t))-x^\mu(p)) + x^\mu(p)] \}_{t=0} = [ \alpha ( \frac{d x^\mu ( \lambda (t))}{dt})_{t=0} + \beta ( \frac{dx^\mu ( \kappa ( t))}{dt} )_{t=0}]
I really don't understand how these two lines are equal at all!!!
And also how can we change the \phi's to x^\mu's in going from eqn 25 to the defn of Z_p(f)?

c) where does eqn 27 come from? isn't ( \frac{\partial}{\partial x^\mu})_p (f) = \frac{\partial f}{\partial x^\mu})_p
is it something like if we compose the numerator with \phi^{-1} then we have to cancel that out by composing the p with \phi to give the \phi(p)? I don't really get why this is allowed though?

d)Where does eqn 29 come from?

Thanks a lot for any help. I really need to get my head round all this vector business over the holidays!

[Office_Shredder]

For a, \lambda(0)=\kappa(0)=p, so once you plug those in you get
\nu(0)=\phi^{-1}(\alpha(\phi(p)-\phi(p)) + \beta(\phi(p)-\phi(p) +\phi(p)) = \phi^{-1}(\phi(p)) = p (not 0 like you say in your post)

For (b), just distribute the derivative linearly. Then \frac{d x^{\mu}(p)}{dt} = 0 because p is just a fixed point, so that's just the derivative of a number

[latentcorpse]

For a, \lambda(0)=\kappa(0)=p, so once you plug those in you get
\nu(0)=\phi^{-1}(\alpha(\phi(p)-\phi(p)) + \beta(\phi(p)-\phi(p) +\phi(p)) = \phi^{-1}(\phi(p)) = p (not 0 like you say in your post)

For (b), just distribute the derivative linearly. Then \frac{d x^{\mu}(p)}{dt} = 0 because p is just a fixed point, so that's just the derivative of a number

hi there. thanks for your answers.

do you have any ideas for c) or d) or also, how we get teh formula for Z-p(f) in the first place?

thanks!