Liquid Mechanics Question

[CollectiveRocker]

If I have a container, filled with water, and a hole is cut in the side at some distance h from the top, how do I go about finding the distance R from the foot of the container that the stream will impact the floor? Do I use Bernouilli's Equation: P1 + ½ pv12 + pgy1 = P2 + ½ pv22 + pgy2 Where P = pressure at depth h, p = density of fluid, and y1 & y2 are = two heights about surface. Or is there another way?

[arildno]

1.By Benoulli, you find the velocity by which the fluid leaves the container (Torricellis law).
2. Use projectile motion to determine R (you'll need to know how high above the ground the hole is)

[CollectiveRocker]

If v = (2gh)^1/2, then we turn to use the kinematic equations. y = H(height from top water level to floor)-h(height of top water level to hole in side of container), we know g, all we're missing is the original velocity, time, and acceleration. Is there something I'm missing?

[e(ho0n3]

Your not missing anything. If you have the velocity, the rest is just simple kinematics.

[CollectiveRocker]

I get R = ((2gh)^(1/2))*t, is this correct?

[arildno]

As long as "t" is the time it takes to reach the ground, yes.