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formulajoe
Oct5-04, 01:58 PM
x(dy/dx) = y*e^(x/y) - x

its either separable, linear, homogeneous, bernoulli or exact. only thing i can figure is that its linear.

how do i break it down to figure it out? the e^x/y is whats throwing me off.

arildno
Oct5-04, 02:06 PM
It's not linear!!
Divide by x.
Note that your right-hand side can now be written as some function g(y/x).

formulajoe
Oct5-04, 02:25 PM
if i break it apart i get dy/dx = (y*e^(x/y) / x) - 1. i can see how it could be separable, but the e^x/y would still be there when i integrate. and that integral would be fairly impossible. i dont see what else it can be.

arildno
Oct5-04, 02:35 PM
Introduce the variable:
v(x)=\frac{y(x)}{x}
We have then:
v'(x)=\frac{y'(x)}{x}-\frac{v}{x}
Or:
y'(x)=xv'(x)+v(x)
Hence, inserting this into your diff. eq., you have:
xv'(x)=ve^{\frac{1}{v}}-(1+v)
This is a separable equation (I wouldn't try solving it, though..)