Gr 11. Thermal Energy *help*

[punk_rawk_jazz]

Does anyone know why I end up with the wrong answer?
The question is:
[QUOTE]Determine the temperature change: 10 kg of water loses 232 kJ or heatQUOTE]

I went delta q is equal to m c delta t, the derived the equation delta t is equal to delta q divded by mc. I therefore did the math as 232 kJ divided by (10 kg times 4.2 x 10 ^3 j/kg C) and got 9.7 x 10 ^4, when the answer was supposed to be 5.5. Does any one know what I did wrong??


Thank you in advance

[Sirus]

Make sure you are consistent in units. Also remember to include signs in your calculations to indicate gain/loss of energy.

[nofx]

Firstly just change the 232 kJ into joules so you that have 232000 J.

q = mc delta t
232000 = 10 * 4200 * delta t
delta t = 232000/10*4200
delta t = 232000/42000
delta t = 5.5

[Diane_]

Was there any particular reason why you posted this twice?

[punk_rawk_jazz]

Nope I just mest up...