Limits!! help!

[johnnyICON]

I have this question that I am not too sure of how to do, can anyone help me?

Evaluate: \lim_{x \to 0} \frac{\sin{x}}{\sqrt{x}}

[Leong]

When x approaches 0, sin x approaches x. so you get
\frac{x}{\sqrt{x}}=\sqrt{x}

[Galileo]

Or remember that \frac{sinx}{x} goes to 1. Then write
\frac{\sin{x}}{\sqrt{x}}=\frac{\sin{x}}{x}\sqrt{x}

[johnnyICON]

awesome, thanks! :smile: