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blackhawk97
Feb15-11, 07:45 PM
A solid sphere of radius R has a non-uniform volume charge density \rho(r) and a constant surface charge density \sigma. If the field inside the sphere is uniform and radially atuned, and the field a distance 2R away from the center is zero, find \rho and \sigma in terms of R, r (distance from the center of the sphere), and Q_\text{volume} (the charge associated with \rho, but not with \sigma).

2. Relevant equations
Gauss's Law

3. The attempt at a solution
I'm not sure how to proceed, but I think the solution should begin by find the total charge on the sphere (ie., adding the integral of the charge calculable from the surface charge density with the integral of the charge calculable from the volume charge density). Am I on the right track?

Matterwave
Feb15-11, 10:27 PM
So, inside the sphere, what does Gauss's law say? Outside the sphere? Try drawing Gaussian surfaces which are spheres inside and outside the sphere of charge.

blackhawk97
Feb16-11, 05:56 PM
I know how to do the first part, i think... (finding \sigma). Basically you just use Gauss's Law

\oint{E \cdot dA}=\frac{Q_\text{enclosed}}{\epsilon_0}

... except you set the r in that equation equal to 2R, so you can ultimately set the expression for the E-field equal to zero and... yeah.

But the part about \rho still has me stumped. Can anyone offer a bit more help?

Also, correction to the problem: the field inside the sphere is not radially atuned, it is directed radially outwards.

betel
Feb17-11, 08:33 AM
So can you express \sigma in terms of Q_{total}?

For the \rho part you have to take Gauss surfaces inside the sphere as Matterwave said.