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1timeuse
Oct12-04, 10:51 PM
Suppose that an ion source in a mass spectrometer produces doubly ionized gold ions (Au2+), each with a mass of 3.27 x 10^-25 kg. The ions are accelerated from rest through a potential difference of 1.40 kV. Then, a 0.600 T magnetic field causes the ions to follow a circular path. Determine the radius of the path.

i tried to use

r = \frac {\sqrt{2mV}}{2q B^2}

i doubled the q because the question says the ions are doubly ionized. is q = 1.6 e -19 still or is it different with gold ions? my answer was 7.95 e -3 but i'm wrong according to my webassign.

Tide
Oct13-04, 12:38 AM
Suppose that an ion source in a mass spectrometer produces doubly ionized gold ions (Au2+), each with a mass of 3.27 x 10^-25 kg. The ions are accelerated from rest through a potential difference of 1.40 kV. Then, a 0.600 T magnetic field causes the ions to follow a circular path. Determine the radius of the path.

i tried to use

r = \frac {\sqrt{2mV}}{2q B^2}

i doubled the q because the question says the ions are doubly ionized. is q = 1.6 e -19 still or is it different with gold ions? my answer was 7.95 e -3 but i'm wrong according to my webassign.

Your denominator also belongs under the radical.