Mastering Partial Fractions for Integrating (x+2)/(x+4)^2

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The discussion focuses on integrating the function (x+2)/(x+4)^2 using partial fractions. The participants mention the decomposition A/(x^2+4) + B/[(x^2+4)^2) with A=0 and B=1, leading to the integral of 1/(x^2+4)^2. There is a suggestion to use the substitution u = 2tan instead of partial fractions for solving the integral. Participants also emphasize the importance of seeking additional resources for understanding the topic better. The conversation highlights the need for clarity in problem-solving and correcting initial mistakes before seeking help.
NINHARDCOREFAN
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The integral of [(x+2/(x+4)]^2

A/(x^2+4) + B/[(x^2+4)^2)

A=0, B=1

so, the integral of 1/(x^2+4)^2

how do you do this?
 
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Let u = 2tan and don't use partial fractions…
 
JonF said:
Let u = 2tan and don't use partial fractions…
I think even when you don't do as what you said in your post, surely you can still find out A LOT OF SOURCES to get this THING solved. Why never look for books around you ? I am sure you should have a lot, because maths computation is what you like, which your presence here already tells me, RIGHT ?

Just a suggestion anyway, since not everyone has an American dream.. For example, me, call me Alexsan, a psychologist-to-be, mainly plays around with alcohols and chemical reactions.
 
NINHARDCOREFAN said:
The integral of [(x+2/(x+4)]^2

A/(x^2+4) + B/[(x^2+4)^2)

A=0, B=1

so, the integral of 1/(x^2+4)^2

how do you do this?
Hehe, Now your turn!

1~ Is it true that you don't understand how to solve the problem or you want to play around with your misinformation?
2~ You first correct your mistake made in your OP, then I will try to help you_UP.

AlexContourPlus
 

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