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sami23
Mar27-11, 11:06 AM
1. The problem statement, all variables and given/known data
The wheel is rigidly attached to gear A, which is in mesh with gear racks D and E. If D has a velocity of v_D = 5 ft/s to the right and wheel rolls on track C without slipping, determine the speed of gear rack E. Set r = 1.4 ft.


2. Relevant equations
angular velocity of gear \omega= v_D / r_D/IC
v_E = \omega * r_E/IC

where r_D/IC = (1.4 + 0.75) = 2.15 ft
and r_E/IC = 0.75 ft


3. The attempt at a solution
\omega = 5 / 2.15 = 2.3256 rad/s
v_E = 2.3256 * 0.75 = 1.744 ft/s to the left but it's wrong

What did I do wrong? Please help

tiny-tim
Mar27-11, 11:32 AM
hi sami23! :smile:
… and r_E/IC = 0.75 ft

why 0.75 ? :confused:

(btw, what does "IC" mean?)

sami23
Mar27-11, 12:09 PM
IC means the instantaneous center of zero velocity where the general formula is: velocity of a point = angular velocity of the body (cross product) distance of the point relative to the IC for a body having general plane motion (doing translation and rotation).

The distance shown in the picture from the center Point O to the track C = 0.75

My mistake... r_E/IC = 1.4 - 0.75 = 0.65 ft