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CrossFit415
Mar27-11, 03:53 PM
Cos70°cos20°-sin70°sin20°

I can't find any of these angles that are equivalent to the basic angles. Thanks

Dick
Mar27-11, 03:59 PM
Do you know a formula for cos(a+b) in terms of the trig functions evaluated at a and b?

CrossFit415
Mar27-11, 04:09 PM
Cost(a+b)=cos a • cos b - sin a • sin b

CrossFit415
Mar27-11, 04:12 PM
I don't know which angles are equivalent to 70° nor 20°

Dick
Mar27-11, 04:20 PM
But you know cos(20+70)=cos(90), right?

CrossFit415
Mar27-11, 04:22 PM
Whoops. Thanks