What magnitude of force must you apply to hold the platform in this position?

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SUMMARY

The discussion focuses on calculating the force required to hold a platform in a leg press exercise, utilizing the principles of spring mechanics. The user performs 72.0 J of work to compress two parallel springs by 0.270 m, leading to the determination of the spring constant (k) using the formula (1/2)k(0.27^2) = 72. The magnitude of force (F) to hold the platform is then calculated using F = kx. Additionally, the user seeks to find the work required to compress the springs an additional 0.270 m and the maximum force needed for this further compression.

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Here's the question that is giving me problems
PLEASE HELP!

Leg Presses. As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arranged side by side so that they are parallel to each other. When you push the platform, you compress the springs. You do 72.0 J of work when you compress the springs 0.270 m from their uncompressed length.

(a) What magnitude of force must you apply to hold the platform in this position?

(b) How much additional work must you do to move the platform 0.270 m farther, and what maximum force must you apply?
 
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Spring law: force= spring constant * distance compressed. (F= kx)

energy: integrating kx dx from a to b, the work done in compressing from a to b is
(1/2)k x2 evaluated between a and b: (1/2)k(b2-a2)

You compress the springs from 0 to .27 and do 72 J of work so
(1/2)k(.272)= 72. You can solve that for k.

Once you know k, You can answer (a) with F= kx.

Moving the platfork "0.270 m farther", you move it from 0.270 to 0.540 m. Since you now know k, you can answer the first part of (b) with (1/2)k((.54)2-(.27)2) and the second part with F= kx.
 
Thank you...u really helped me out
 

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