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afirican
Oct20-04, 04:51 PM
If N is a normal subgroup of G and |G/N| = m, show that x^m is in N for all x in G

Hurkyl
Oct20-04, 05:00 PM
Well, clearly G/N should have some pivotal role in this statement. Maybe you should move the problem from G to G/N to see if that helps.