What is the L/R constant for this series circuit?

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SUMMARY

The L/R constant for the given series circuit, which includes a 4K resistor, a 1mH inductor, and a 1K resistor connected to ground, is established as 1 microsecond (1us). The total resistance affecting the L/R constant is the sum of the resistances in the circuit, specifically the 1K resistor and the inductor. The 4K resistor does not influence the L/R constant in this context. The magnitude response for the circuit should be plotted on a Bode plot, indicating negative values for voltages less than the supply.

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Homework Statement


Consider the series circuit with

supply -- resistor (4K) -- inductor (1m) -- resistor (1K) -- groud


Homework Equations


I just don't know. According to the answer sheet it's 1us.

The Attempt at a Solution



Reverse engineering from this implies it's only the inductor and resistor connect to ground (1K) that influence the L/R... why not the 4K!?


Thanks
Thomas
 
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That can't be right, because the "R" in L/R is total resistance.
 
Basically using that circuit I need to plot the freq-magnitude response on a bode plot... that is the mag response between the inductor, 1k and ground. Let's call this point X. The magnitude response is X/supply. On a bode plot is should be negative (or 0) as the voltage across the 2 components is a fraction of the original and on a bode plot, numbers <1 are -ve.
 

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