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ObliviousSage
Apr19-11, 08:45 PM
If X is some RV, and Y is a sum of n independent Xis (i.e. n independent identically distributed random variables with distribution X), is the mean of Y just the sum of the means of the n Xs?

That is, if Y=X1+X2+...+Xn, is E[Y]=nE[X]?

I know that for one-to-one order-preserving functions, if Y=h(X) then E[Y]=E[h(X)] with a single variable X, but I'm not sure if it works with multiple Xs, even with something as simple as addition.

mathman
Apr20-11, 04:08 PM
The mean of a sum is the sum of the means. The terms in the sum do not have to be independent or have the same distribution.

ObliviousSage
Apr20-11, 07:36 PM
The mean of a sum is the sum of the means. The terms in the sum do not have to be independent or have the same distribution.

Awesome, I wasn't sure. Thanks for clearing that up!