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jbmap
Oct24-04, 07:44 AM
Hi everyone, I was hoping someone could help me with something. Could someone explain to me exactly what this expression means:

H = {(a+b) + (a - 2b)t + bt^2 | a E R, b E R}

the purpose is to find the dimension of the given subspace, which I know how to do, I have just never seen this notation, so I'm not exactly sure what this expresssion is telling me about the subspace. since a and e are real numbers, does that mean t is not necessarily a real number? and is the first part of the expression a single vector? or is it some sort of conglomeration of multiple vectors? Thanks for your help
Davy

Galileo
Oct24-04, 01:31 PM
I think you are looking at a vector space of polynomials (of degree 2 or higher).
A set basis vectors could be: \{1,t,t^2,t^3,...,t^n\}
Then H=\{(a+b)+(a-2b)t +bt^2|a \in \mathbb{R}, b \in \mathbb{R}\}
would be a subspace of the polynomial space.
So, formally speaking, t is not a number, but a vector.

HallsofIvy
Oct24-04, 01:33 PM
You also posted this under "linear algebra" and were given very good answers there.

The "notation" means that H is the subset of all quadratic polynomials
α+ βt+ γt2 such that α= a-b, β= a- 2b, and γ= b.

The set of all quadratic polynomials has dimension 3 specifically because we can select any of the coefficients α, β, γ arbitrarily: a basis is { 1, t, t2}.

Here the coefficients depend upon only two numbers. Pick a or b arbitrarily and then you can calculate α, β, γ .

In particular, if you take a= 1, b= 0, the polynomial is 1+ t and if you take a= 0, b= 1, the polynomial is 1- 2t+ t2. A basis for H is {1+t, 1- 2t+ t2} so H has dimension 2.