Bare potential energy equation

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SUMMARY

The discussion centers on the bare potential energy equation and its implications for understanding the forces acting on an electron. The user explores the relationship between potential energy and work done by electric forces, specifically using the equation Uf = -∫(E * Q) dr. They express confusion regarding the assumption that an electron's charge is effectively doubled in the calculations, leading to a misunderstanding of the forces involved. The user seeks clarification on why the potential energy equation appears to account for the electron's charge twice, despite having only one charge present.

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  • Understanding of electric potential energy and its equations
  • Familiarity with calculus, particularly integration techniques
  • Knowledge of electrostatics, including Coulomb's law
  • Basic concepts of charge distribution and field theory
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Students of physics, particularly those studying electromagnetism, educators explaining potential energy concepts, and anyone seeking to deepen their understanding of electric forces and charge interactions.

Zaphodx57x
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I am having a problem understanding this problem which references this exercise .

I tried it a couple different ways. I used
[tex]\begin{multline*}<br /> \Delta U(Potential Energy) = Uf - Ui = Uf - U(r = infinity) = Uf - 0 \\<br /> dU = Uf = -W = \int F * ds = \int E * Q * ds \\<br /> Uf = -\int E * Q * dr = -\int \frac{kqQ}{r^2} = \frac{kqQ}{r}<br /> \end{multline*}[/tex]
I also tried using the bare potential energy equation and using two arbitrary surface areas (dA) on opposite sides of the sphere with a distance between charges of 2r , then integrating each over just half of the sphere, which provided the same result.
The problem I have is that this result gives me a pretty decent result for the mass of an electron if I assume that q = Q = charge of an electron. But this assumption seems to say that the electron is pushing against itself by its full charge.
That is a force [itex]\frac{QQ}{r^2}[/itex] is present instead of a [itex]\frac {(Q)(q}{r^2}[/itex] where [itex]q = \frac {Q}{n}[/itex] or some other fractional or modified charge.
This almost makes sense to me in that if a sphere were to have a charge spread evenly over its surface and its radius is infinity, it still acts as if it has all its charge at its center and therefore would resist a decreasing radius of like charge.

If anyone can find a way to explain why this problem makes sense I would really appreciate it. I just don't understand how the Potential energy can contain the electron's charge twice, when there is only one charge to begin with.
 
Last edited:
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Oops, I posted this in the wrong place, i'll repost in the homework section.
 

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