View Full Version : Can anyone graph this?
crazynut52
Oct24-04, 04:02 PM
r(t)= <t^2, cost, sint>
Does anyone have a graphing program to make a picture of this, thanks.
graphic7
Oct24-04, 04:05 PM
r(t)= <t^2, cost, sint>
Does anyone have a graphing program to make a picture of this, thanks.
What kind of range are you looking for?
I assume this is a vector field?
crazynut52
Oct24-04, 04:10 PM
its a curve of that function. I'm not sure on the range, I guess just enough to show the pattern. I believe it is a cos sin circle coming out the x axis.
graphic7
Oct24-04, 04:24 PM
Try this:
http://graphical.shacknet.nu/image1.jpg
Tom Mattson
Oct24-04, 04:25 PM
The implied range is that x>0, and that y and z must both be between -1 and 1 (inclusive). I don't have a graphing utility handy, but what I would do is find the 2D curve in each coordinate plane by eliminating the parameter. So, in the xy plane, you have y(x)=arccos(x1/2), in the xz plane you have z(x)=arcsin(x1/2), and in the yz plane you have y2+z2=1.
Basically, the curve is constrained to the unit cylinder y2+z2=1, and as it goes around it moves forward on the x-axis, starting from x=0.
graphic7
Oct24-04, 04:29 PM
The implied range is that x>0, and that y and z must both be between -1 and 1 (inclusive). I don't have a graphing utility handy, but what I would do is find the 2D curve in each coordinate plane by eliminating the parameter. So, in the xy plane, you have y(x)=arccos(x1/2), in the xz plane you have z(x)=arcsin(x1/2), and in the yz plane you have y2+z2=1.
Basically, the curve is constrained to the unit cylinder y2+z2=1, and as it goes around it moves forward on the x-axis, starting from x=0.
My plot seems to agree.
graphic7
Oct24-04, 04:33 PM
If you need a larger range, just request it.
Tom Mattson
Oct24-04, 04:47 PM
If you need a larger range, just request it.
There is no larger range. The implied range that I stated is the maximal range.
graphic7
Oct24-04, 04:49 PM
There is no larger range. The implied range that I stated is the maximal range.
Only in the y and z directions, though. I just replotted from 0 to 1000 and you really get to see the unit cyclinder take form.
Tom Mattson
Oct24-04, 04:53 PM
Only in the y and z directions, though. I just replotted from -1000 to 1000 and you really get to see the unit cyclinder take form.
Ah, I see what you're saying. You mean a larger range in your picture. What I was saying is that the range implied by the equations is the maximal range, and that if there is any modification to that range in the problem, it can only be smaller, not bigger.
graphic7
Oct24-04, 04:55 PM
Ah, I see what you're saying. You mean a larger range in your picture. What I was saying is that the range implied by the equations is the maximal range, and that if there is any modification to that range in the problem, it can only be smaller, not bigger.
Ah, sorry for the confusion.
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