FedEx
Jul2-11, 01:19 AM
Hi,
I want to solve a differential equation which goes like this..
\nabla^{2}\psi = A\psi
For an annulus having inner diameter as a and outer diameter as b. (A is some constant)
I can write down the laplacian in polar co-ordinates and carry on and get a bessel function as the solution.. And then apply the boundary conditions that at r=a and r=b \psi = 0
Will this do? Or will i have to incorporate the structure of the annulus in the equation like making a co-ordinate transform from r to r-a etc..
I want to solve a differential equation which goes like this..
\nabla^{2}\psi = A\psi
For an annulus having inner diameter as a and outer diameter as b. (A is some constant)
I can write down the laplacian in polar co-ordinates and carry on and get a bessel function as the solution.. And then apply the boundary conditions that at r=a and r=b \psi = 0
Will this do? Or will i have to incorporate the structure of the annulus in the equation like making a co-ordinate transform from r to r-a etc..