View Full Version : Friction Problem
The coefficient of friction between a certain brass block and a large revolving turntable is µ = 0.26. How far from the axis of rotation can the block be placed before it slides off the turntable if it is rotating at 33 1/3 rev/min?
:confused: :yuck: :frown: :grumpy: :surprised :rofl:
Consider that it is friction that supplies the centripetal force.
As long as the force that is needed to overcome friction is larger than the centripetal force the block will not move.
F_{friction} = F_z \mu = mg\mu
F_{centripetal} = \frac{mv^2}{r}
so you can move the block from the axis of rotation until these are equal, and when they are equal this holds:
mg\mu = \frac{mv^2}{r} \Leftrightarrow g\mu = \frac{v^2}{r}
and using v = r*v_{rotational} you can solve this
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.