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3.14lwy
Nov7-04, 04:21 AM
if
Xn = x^n + x^(n-2) + x^(n-4) + ... + 1/[x^(n-4)] + 1/[x^(n-2)] + 1/(x^n)
(where n is a non-negative integer)

then ,

X1 = x + 1/x

X3 = x^3 + x + 1/x + 1/(x^3)



What s the value of X2??

X2 = x^2 + x^0 + 1/(x^2) = x^2 + 1 + 1/(x^2)

or X2 = x^2 + x^0 + 1/(x^0) + 1/(x^2) = x^2 + 1 + 1 + 1/(x^2)
????

Zurtex
Nov7-04, 08:30 AM
In your definition you decreased the power of x by 2 each time, so:

x2 = x^2 + x^0 + x^{-2} = x^2 + 1 + \frac{1}{x^2}

For x \neq 0