Simple application of Derivitives problem

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SUMMARY

The discussion focuses on finding two positive numbers whose product is 192 while minimizing their sum. The user correctly identifies the relationship between the variables as x*y=192 and y=192/x. They also derive the derivative dy/dx=-192/x^2 but express confusion regarding setting the derivative to zero for finding local extrema, noting that -192/x^2 cannot equal zero. The solution involves minimizing the function x + 192/x.

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Leonidas
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Find two positive numbers that satisfy the given requirements.


The Product is 192 and the sum is a minimum.


I said that x*y=192 and y=192/x and that dy/dx= -192/x^2

I thought that we were supposed to set the derivative equal to zero in order to find the local extrema... however -192/x^2 does not equal 0...right?

I'm dazed and confused... can someone please help?
 
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You should have done

[tex]xy = 192[/tex]

[tex]y = \frac{192}{x}[/tex]

[tex]x + y = (number)[/tex]

Minimize this:
[tex]x + \frac{192}{x} = (number)[/tex]
 
oh.

...

1. That was really fast... thanks.

2. I should have seen that.

3. :smile:
 

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