HobieDude16
Nov7-04, 03:26 PM
well, ive tried, and ive tried, but i cant seem to get this one right, my TA did it in class, but left something out i think, he did it in a big hurry, so i cant get an answer thats right.... ill show you what ive tried, and maybe you can spot my error? any help is much appreciated
Figure 11-49 is an overhead view of a thin uniform rod of length 0.600 m and mass M that is rotating horizontally at 80.5 rad/s counterclockwise about an axis through its center. A particle of mass M/3.00 and speed 41.5 m/s hits the rod and sticks. The particle's path is perpendicular to the rod at the instant of the hit, at a distance d from the rod's center.
http://www.webassign.net/hrw/W0247-N.jpg
(a) At what value of d are rod and particle stationary after the hit?
m
ok, so our ta worked out the cross produt of r and the particle, and used that to get the equation (1/12)mL^2 omega^2-d(m/3)v=0.... so you sove that out, and get d=(L^2omega^2)/4v but thats just not right... what am i doing wrong? any help? thanks in advance
John
Figure 11-49 is an overhead view of a thin uniform rod of length 0.600 m and mass M that is rotating horizontally at 80.5 rad/s counterclockwise about an axis through its center. A particle of mass M/3.00 and speed 41.5 m/s hits the rod and sticks. The particle's path is perpendicular to the rod at the instant of the hit, at a distance d from the rod's center.
http://www.webassign.net/hrw/W0247-N.jpg
(a) At what value of d are rod and particle stationary after the hit?
m
ok, so our ta worked out the cross produt of r and the particle, and used that to get the equation (1/12)mL^2 omega^2-d(m/3)v=0.... so you sove that out, and get d=(L^2omega^2)/4v but thats just not right... what am i doing wrong? any help? thanks in advance
John