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zetafunction
Aug2-11, 04:07 PM
let be a function so \frac{1}{T}\int_{0}^{T}f(x)dx =0
as T--->oo does it man that the function f(x) tends to ' as x--->oo what if 'f' is an oscillating function ??
HallsofIvy
Aug3-11, 09:15 AM
let be a function so \frac{1}{T}\int_{0}^{T}f(x)dx =0
as T--->oo does it man that the function f(x) tends to ' as x--->oo
I have no clue what you mean by that. What does ' mean?
what if 'f' is an oscillating function ??
Well, did you try an example? What if f(x)= sin(x)?
The integral oscillates (and is bounded) but the denominator gets larger and larger. The limit is 0.
Nebuchadnezza
Aug3-11, 09:28 AM
I think "zetafunction" means
\lim_{T \to \infty } \frac{1}{T} \int_{0}^{T} f(x) dx
Just quote my post, to see how I made it.
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