PDA

View Full Version : Derivitive


Leonidas
Nov14-04, 05:36 PM
I keep on getting a weird answer when i take the dy/dx for this...
y=x(1-x^2)^1/2

i got x(1/x^2)^(-1/2)*-2x + (1-x^2)^(1/2)

... did i do that correctly?

kreil
Nov14-04, 06:13 PM
y=x(1-x^2)^\frac{1}{2}

Use product rule/chain rule:


y=(x)(\frac{1}{2})(\frac{1}{\sqrt{1-x^2}})(-2x) + (1-x^2)^\frac{1}{2}


Slightly more simplified:


y=(\frac{-x^2}{\sqrt{1-x^2}}) + (1-x^2)^\frac{1}{2}


Pretty sure thats the answer...if so you aren't using the chain rule correctly. Double check how you get the derivitive of (1-x^2)^\frac{1}{2}

Leonidas
Nov14-04, 06:27 PM
DUH. *slaps self on forhead* .... heh... forgot a single step and it screwed me up (of course).

Thanks.