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ElectricMile
Nov17-04, 09:58 PM
ok..haveing trouble understanding some examples in the book....

1) 1000kg rocket is fired striat up, need rocket to escape and never return. what speen does rocket need to escape from grav pull to never come back?(non rotating earth)

i know rocket cant stop so or it will be drawn back into earth. so...
K2+U2=K1+U1 is:
0+0=(1/2)m*v^2 - (GMm)/R)

whats with the 0+0?

then it goes to:
Vescape= v1 = SQRT(2GM/R)

howd they get to that equation??
i know the answers and stuff its in the book, i just dont know how they got to those equations

thecolor11
Nov17-04, 11:05 PM
For escape velocity, you only need enough speed so that you escape the gravitational potential of the object. Therefore, any kinetic energy at infinity would be wasteful. So K2 = 0. U2 = 0 because the gravitational potential falls off like 1/r which goes to zero at infinity.

So we have (1/2)m*v^2 = GmM/R

so v^2 = 2GM/R

v = sqrt(2GM/R)

ElectricMile
Nov17-04, 11:17 PM
still not sure how you got rid of the 1/2...and did the m just cancel out on each side?

Zlex
Nov17-04, 11:28 PM
still not sure how you got rid of the 1/2...and did the m just cancel out on each side?

(1/2)m*v^2 = GmM/R

1] Divide both sides by m

(1/2)*v^2 = GM/R

2] Times both sides by 2

v^2 = 2GM/R

3] Take the root

v = sqrt(2GM/R)

gnome
Nov17-04, 11:33 PM
You can often find your answers by searching previous threads, like this one from Tuesday night:
http://www.physicsforums.com/showthread.php?t=52967