Solve a Simple Power Problem: Escalator Work Rate

[pinky2468]

I am not sure why I am stumped on this problem, but here it is

An escalator 30.0 meters long slants 30degrees relative to the horizontal. If it moves at 1.00m/s at what rate does it do work in lifting a 50kg man from the bottom to the top?

Any suggestions on where to start?

 

[krab]

work done in lifting is mgh, so power is time derivative: mg dh/dt. dh/dt is the vertical component of the velocity. Since you have the velocity magnitude and direction, you can figure out the vertical component.

 

[pinky2468]

What does the d stand for. Do I need to find the height by using sin 30?

 

[Physics is Phun]

I have a feeling you don't know calculus. d stands for derivative or change in. your formula for power is P= mgh/t all you have to do is figure out the height using sin30 with your length and your time with sin30 your speed.