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Gughanath
Nov20-04, 03:51 PM
The angle between a 40N Force and a 70N is 60 degrees....how do i workout the resultant force and direction?

vsage
Nov20-04, 03:55 PM
Take the 70N force to lie on the polar axis (+x axis). The vector component of this force is then 70N <cos(0), sin(0)> while the 40N force is given by 40N<cos(60), sin(60)>. Sum the i and j components of these vectors and that's the resultant force. The direction is given by tan^-1(j component / i component)